Physics, asked by thewalkthrougher1234, 8 months ago

in the arrangement shown in the figure, find the acceleration of m. the pulleys are light. the strings are massless. neglect the dimension of pulleys and masses.​

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Answered by aaravs618gmailcom
0

Now, according to question, m

1

moves with

constant velocity

⇒a

1

−a=0⇒

a

1

=a

....(i)

From figure above ,

T−m

1

g=0⇒T=m

1

g=1×9.8

T=9.8N

.....(ii)

2T=Ma

Ma=19.6

(from (ii)) ...... (iii)

m

2

g−T=a+a

1

=29 (from (i))

⇒2a=2×9.8−9.8

a=

2

9.8

=4.9m/s

2

putting in (iii)

M=

4.9

19.6

M=4kg

solution

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