Question

In the arrangement shown m1=300kg,m2=400kg, the system is in equilibrium the tension in the rope is

Answer 1

Explanation:

M1=300kg

M2=400kg

300kg +400kg

=700kg

Answer 2

The tension in the rope is 3428.57N.

Given:-

Mass of first object = 300kg

Mass of second object = 400kg

To Find:-

The tension in the rope.

Solution:-

We can easily find out the value of tension in the rope by using these simple steps.

As

Mass of first object (m1) = 300kg

Mass of second object (m2) = 400kg

Tension in rope (t) =?

According to the formula of tension in the pulley block system,

$t = \frac{2m1 \times m2 \times g}{m1 + m2}$

on putting the values of m1 and m2 in above equation,

$t = \frac{2 \times 300 \times 400 \times 10}{300 + 400}$

$t = \frac{600 \times 4000}{700}$

$t = \frac{2400000}{700}$

$t = \frac{24000}{7}$

$t = 3428.57$

Hence, The tension in the rope is 3428.57N.

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