Question

In the arrangement shown, neglect the mass of the ropes and the pulley. What must be the value of m to keep the system in equilibrium ? (Neglect friction every where)

Figure in attachment . ​

Answer 1

Take take the force on A T2 and on weight 2 T1 Now, T1=mg T2 = 2gsin30°+T1 ( T1 will balance T2) T2 = 2gsin30°+ 2g T2 = 2g.1/2+2g T2 = g+2g T2 = 3g T2=mg mg = 3g m= 3kg

Answer 2

Answer:

HOpe iT HelP YOu DEaR.....