In the arrangement shown, neglect the mass of the ropes and the pulley. What must be the value of m to keep the system in equilibrium ? (Neglect friction every where)
Figure in attachment .
Attachments:
Answers
Answered by
4
Take take the force on A T2 and on weight 2 T1 Now, T1=mg T2 = 2gsin30°+T1 ( T1 will balance T2) T2 = 2gsin30°+ 2g T2 = 2g.1/2+2g T2 = g+2g T2 = 3g T2=mg mg = 3g m= 3kg
Answered by
5
Answer:
HOpe iT HelP YOu DEaR.....
Attachments:
Similar questions