Question

In the arrangement shown tension in the string connecting 4 kg and 6 kg masses is

Answer 1

"normal reaction on the block of mass 2 kg = f1 = 2×g = 2×10 = 20N

Now,

the tension in the string between the block of mass 2kg and the block of mass 4 kg = 20*frictional force

= 20*f

= 20*μf1

= 20 - 4

= 16N

Now,

the friction acting on the block of mass 4 kg = f2

= μmg

= 0.2*4*10

= 8N"