Question

In the arrangement shown tension in the string connection4 kg and 6 kg masses is
(a) 8N (b) 12N (c) 6N (d) 4N

Answer 1

HELLO DEAR,

normal reaction on the block of mass 2 kg = f1 = 2×​g = 2×​10 = 20N

Now,

the tension in the string between the block of mass 2kg and the block of mass 4 kg = 20*frictional force

= 20*f

= 20*μf1

= 20 - 4

= 16N

Now,

the friction acting on the block of mass 4 kg = f2

= μmg

= 0.2*4*10

= 8N

now the tension in the string between the mass of 2 kg and the mass of 8 kg = 16 - 8 = 8N

HENCE, Option ( A ) is the correct

I HOPE ITS HELP YOU DEAR,

THANKS

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