Question

In the arrangement shown the mass m will ascend with an acceleration

Answer 1

Be with a proper question

Answer 2

Given :-

${m}_{1} = m$

${m}_{2} = \dfrac{3}{2}m$

As we know a relation about Pulley when two objects are hanged.

$a=\dfrac{{m}_{2}-{m}_{1}}{{m}_{2}+{m}_{1}}g$

a = [(3/2m - m)/(3/2m + m)]g

a = [m/2 × 2/5m]g

a = g/5

Hence,

The acceleration of the body = a = g/5.

For Tension we use a formula,

T = [(2m1m2)/(m1+m2)]g