Question

In the arthematic series the sum of first 12 terms is 348 the sum of first 11 terms is 341 and the sum of first 10 term is 330 find the first term

Answer 1

First term = 51

Step-by-step explanation:

sum of first 12 terms is 348

sum of first 11 terms is 341

sum of first 10 term is 330

=> 12th term  =  sum of first 12 terms - sum of first 11 terms

= 348 - 341

= 7

12th term = 7

11th term =   sum of first 11 terms - sum of first 10 term

= 341 - 330

= 11

11th term = 11

d = Common difference = 12th term - 11 th term

= 7 - 11

= - 4

a = First term

11 th term = a + 10d

=> 11 = a + 10(-4)

=> a = 51

First term = 51

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Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

sum of first 12 terms is 348

sum of first 11 terms is 341

sum of first 10 term is 330

=> 12th term = sum of first 12 terms - sum of first 11 terms

= 348 - 341

= 7

12th term = 7

11th term = sum of first 11 terms - sum of first 10 term

= 341 - 330

= 11

11th term = 11

d = Common difference = 12th term - 11 th term

= 7 - 11

= - 4

a = First term

11 th term = a + 10d

=> 11 = a + 10(-4)

=> a = 51

First term = 51