In the atom of an element "Z" , 5 electrons are present in the configuration shell. It requires noble gas configuration by accepting requisite number of electrons, then what will be the charge on the so formed? Write the formula of the compound which will be formed when "Z" acts with 'Na' atom.
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Z= No of Proton = Electron
= 5
Boron have Z = 5
it need three more ele then charge will be or can loss three ele too
so possiblity are +3 , -3
Na3B will be the compound formed
= 5
Boron have Z = 5
it need three more ele then charge will be or can loss three ele too
so possiblity are +3 , -3
Na3B will be the compound formed
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