In the balanced reaction? XS+ YHNO3 -> ZH2SO4+mNO2+nH2O . The value of Y^2-X^2/Z+m
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To balance the number of iodine atoms, HI is multiplied with 2.
Iodine is oxidized. Its oxidation state changes from −1 to 0. Net increase is +2.
Sulphur is reduced. Its oxidation state changes from 6 to −2. Net decrease is 8.
To balance the net increase and net decrease in the oxidation number, factor 4 is used. Thus, coefficients of HI and I
2
are multiplied by 4.
To balance oxygen atoms, four water molecules are required on the right.
Thus, x=8, y=4 and z=4.
Explanation:
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