Question

In the beginning of meiosis a meiocyte has 16 pg of DNA .the amount in a gamete will be

Answer 1

• At the beginning of meiosis, a meiocyte has 16 of DNA.

•The initial step of meiosis has 16 of

DNA.

• Two haploid cells are formed at the last stage of meiosis.

• Stage one 16pg = 8pg+ 8pg

Second stage= 4pg+4pg+4pg+4pg

• So the answer is 4pg

• The amount in a gamete will be 4pg

• Meiocyte is a cell it is divided into gametes through the meiosis process.

Answer 2

The amount in a gamete will be 8p

Explanation:

meiocyte=2n=16pg  

Gamete=n=16/2=8p

• In the meiocyte the gamete is formed due to the cell differentiation.
• During this cycle they divide into four haploid gametes after the division of two diploid cells.
• This division of cells varies from organisms to organisms. These cells are mostly present in the organisms that produce sexually.
• The gametes which carry the chromosomes are mainly divided into male and the female gametes.
• These types of divisions are mainly responsible for maintaining the chromosome numbers