Question

In the below fig, angle ACB = 40°. Find angle OAB

No illrevent answer please
and its urgent ​

Answer 1

We know that angle formed by a chord at the center is double the angle formed by same chord at any other point in the circle.

So AOB = 2 x ACB

AOB = 80 degree.

Now since OA and OB are radii , hence they are equal.

So OAB = OBA

Now we know that , In Triangle

AOB + OBA + OAB = 180 DEGREES

80 DEGREES + OAB + OAB = 180 degrees ( since OBA = OAB)

2OAB = 100 degrees

OAB = 100/2

OAB = 50 degrees

Answer 2

Answer:

angle OAB = 50°

Step-by-step explanation:

arc AB = angle ACB/2. inscribed angle

hence, angle aob =80

oa=ob radii of same circle

hence oab=oba triangle aob is an isosceles triangle

oab+oba+80=180

hence angle OAB = 100/2

=50=