Question

In the below figure AB and BC are two chords of a circle with centre 'O'.Diameter BD bisects angle ABC.show that AB=BC​

Answer 1

$\huge\bold\red{HELLO!}$

Step-by-step explanation:

In ∆BAD and ∆BCD,

∠BAD = ∠BCD since 90° each,

as angle in a semicircle is a right angle,

BD = BD common

BA = BC Chords equidistant from the centre ar equal in length

⇒ ∆BAD ≅ ∆BCD RHS

⇒∠ABD = ∠CBD

∠ADB = ∠CDB CPCT

⇒diameter BD bisects ∠ABC and ∠ADC