Question

in the below figure, ABCD is a quadrilateral and BE ll AC and also BE meets DC produced at E. show that area of triangle ADE is equal to the area of the quadrilateral ABCD​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

here the answer in explanation

Step-by-step explanation:

area(ABCD) = area(ADC) + area(ABC)(1)

area(ADE) = area(ADC) + area(ACE)(2)

so, area(ABCD) = area(ADE) if area(ABC) = area(ACE)

In triangle ABC and ACE,

They have a common base i.e. AC and they have a same height because they are between the same parallel.

Therefore, area(ABC)=area(ACE)(iii)

So, from (iii) we can say that area(ABCD)=area(ADE)

Hope you understood. By the way this is my first answer in BRAINLY.