In the below figure, AD = CD and AB = CB
(i) State the three pairs of equal parts in ΔABD and ΔCBD.
(ii) Is ΔABD ≅ ΔCBD? Why or why not?
(iii) Does BD bisect ∠ABC? Give reasons.
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(i) In ΔABD and ΔCBD,
AB = CB
AD = CD
BD = BD
(ii) Yes, it is congruent by SSS congruence criterion.
(iii) Since ΔABD ≅ ΔCBD,
∠ABD = ∠CBD
Hence, BD divides ∠ABC into 2 equal parts.
Therefore, BD bisects ∠ABC.
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