In the below figure, angle abc=69°,angle acb=31°, find angle bdc.
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Angle ABC = 69°
and
Angle ACB =31°
Use angle sum property of Triangle
Therefore
69°+31° + angle BAC = 180°
Angle BAC= 180° - 100°
Hence, angle BAC = 80°
As we can see that
angle BDC and angle BAC lie on the same side of the segmemt and are extended from the same arc.
Therefore,
Angle BDC = Angle BAC
Hence, angle BDC= 80°.
and
Angle ACB =31°
Use angle sum property of Triangle
Therefore
69°+31° + angle BAC = 180°
Angle BAC= 180° - 100°
Hence, angle BAC = 80°
As we can see that
angle BDC and angle BAC lie on the same side of the segmemt and are extended from the same arc.
Therefore,
Angle BDC = Angle BAC
Hence, angle BDC= 80°.
Answered by
6
Hello mate =_=
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Solution:
∠ABC+∠ACB+∠BAC=180°
⇒69°+31°+∠BAC=180°
⇒∠BAC=180°−69°−31°=80° ........(1)
∠BAC=∠BDC (Angles in the same segment are equal) .......(2)
From (1) and (2), we can say that
∠BDC=80°
hope, this will help you.
Thank you______❤
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