Math, asked by hiral22, 1 year ago

In the below figure, angle abc=69°,angle acb=31°, find angle bdc.

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Answers

Answered by allysia
10
Angle ABC = 69°
and
Angle ACB =31°
Use angle sum property of Triangle
Therefore
69°+31° + angle BAC = 180°
Angle BAC= 180° - 100°

Hence, angle BAC = 80°

As we can see that
angle BDC and angle BAC lie on the same side of the segmemt and are extended from the same arc.

Therefore,

Angle BDC = Angle BAC

Hence, angle BDC= 80°.
Answered by Anonymous
6

Hello mate =_=

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Solution:

∠ABC+∠ACB+∠BAC=180°

⇒69°+31°+∠BAC=180°

⇒∠BAC=180°−69°−31°=80°       ........(1)

∠BAC=∠BDC  (Angles in the same segment are equal)      .......(2)

From (1) and (2), we can say that

∠BDC=80°

hope, this will help you.

Thank you______❤

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