Question

In the below Figure, BA || ED and BC || EF.
Show that
angle ABC = angle DEF​

Answer 1

Answer:

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Step-by-step explanation:

cause this angle def is a reflected angle so if u make the angle proper then it is equal

Answer 2

DE intersect BC at P

EF||BC & DP is transversal

∠ DEF = ∠ DPC . . . . . . . . ( i )

Now, AB||DP & BC is transversal

∠ DPC = ∠ ABC . . . . . . . ( ii )

From ( i ) & ( ii ),

we get :

∠ ABC = ∠ DEF

Hence , proved