Question

In the below figure BC is the diameter of circle and angle BAO =60,then find angle ADC?

Answer 1

Answer--

∠ADC = 60°

Step-by-step explanation:

In ΔAOB,

∠OBA = ∠BAO

[angles opposite to equal sides are equal]

∠OBA = 60° [∴ ∠BAO = 60°, given]

∠ABC=∠ADC

[angles in the same segment AC are equal]

so ∠ADC = 60°