Question

In the below figure, /_EBC = 115º and /_DAB = 100°. Find /_ACB. ​

Answer 1

Answer:

Given,

   ∠DAB = 100°

     => ∠BAC = 180° - 100° = 80°

   ∠EBC = 115°

     => ∠ABC = 180° - 115° = 65°

By the angle sum property of the triangle,

         in ΔABC ,

           ∠BAC + ∠ABC + ∠ACB = 180°

         => 80° + 65° + ∠ACB = 180°

         => ∠ACB = 35° (Ans.)

        Hope it helps

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