Question

in the below figure if ab parallel cd parallel ef. pq parallel rs angle rqd=25 degrees and anglecqp=60 degrees.then find angleqrs and anglerqp​

Answer 1

Step-by-step explanation:

Given figure, if AB || CD || EF, PQ || RS, RQD=25o and CQP=60o,

Then ∠SRB=∠CQP=60 degree

OR ∠QRA=∠RQD=25 degree

So ∠ARS+∠SRB=180 degree

∴∠ARS=120−60=120degree

∠QRS=∠ARS+∠QRA=120+25=145 degree..

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