Question

In the below figure, if TP and TQ are the two tangents to a circle with centre O so that angle POQ =110°, then angle PTQ is equal to ?

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Answer 1

Step-by-step explanation:

hope this will be helpful for u

Answer 2

Answer:

TP and TQ are tangent to a circle so

angleOPT = angleOQT =90°

thus,

in quadrilateral OPTQ,

angleOPT + anglePTQ + angleOQT + anglePOQ = 360°

SO,

90° + anglePTQ +90° + 110° = 360°

290° + anglePTQ = 360°

anglePTQ=360°-290°

anglePTQ=70°

THAT'S ALL

THANK YOU.