in the below figure O is the centre of a circle such that diameter AB= 13 cm and AC= 12 cm
BC is join find the area of the shaded region
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area of semicircle = 1/2 ×22/7 × 6.5×6.5 = => 66.39 cm²
(BC) ² =(AB) ² - (AC) ²
BC² = 169 - 144 = 25
BC = 5 CM
Area of triangle = 1/2 ×5×12 = 6×5 = 30cm²
Area of shaded portion = (66.39- 30 )cm²
= 36.39 cm²
(BC) ² =(AB) ² - (AC) ²
BC² = 169 - 144 = 25
BC = 5 CM
Area of triangle = 1/2 ×5×12 = 6×5 = 30cm²
Area of shaded portion = (66.39- 30 )cm²
= 36.39 cm²
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