Question

In the below figure PSR RTQ and PAQ are three semicircles of diameter 10 cm 3 cm and 7 cm respectively find the perimeter of the shaded region. (Use pie= 3.14)

Answer 1

p(psr)+p(paq)+p(tqr)

1/2[2*22/7*(5+3.5+1.5)]

1/2[2*22/7*(10)]

*22/7*(10)

31.4

Answer 2

Answer:

15.42 cm

Step-by-step explanation: pie=3.14

perimeter of semicircle (p) = (2+pie)d/2   ...............(1)

p [PSR]=(2+3.14)10/2

           =(5.14)5

           =25.7

p [PAQ]=(2+3.14)7/2

            =(5.14)3.5

            =17.99

p [QTR]=(2+3.14)3/2

            =(5.14)1.5

            =7.71

Perimeter of shaded part={ (p[PSR]-p[PAQ])+p[QTR]} ............(construction)

                                ={(25.7-17.99)+7.71}

                               ={(7.71)+7.71}

                               =15.42

Hence. perimeter of shaded part is 15.42