Math, asked by devanshi7985, 1 year ago

In the below figure PSR RTQ and PAQ are three semicircles of diameter 10 cm 3 cm and 7 cm respectively find the perimeter of the shaded region. (Use pie= 3.14)

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shubham6948: hii

Answers

Answered by blowny

p(psr)+p(paq)+p(tqr)

1/2[2*22/7*(5+3.5+1.5)]

1/2[2*22/7*(10)]

*22/7*(10)

31.4

Roshan1694: thnqs bro

blowny: please mark it brainliest

spurthi122: pie=3.14 you have taken 22/7

blowny: but 22/7=3.14 that much common sense is applicable

spurthi122: then why the hell is it mentioned (pie=3.14)

blowny: i hv not taken pie but directly 22÷7 open ur calculator solve it out you will get 31.4 each and every time you calculate

Answered by spurthi122

Answer:

15.42 cm

Step-by-step explanation: pie=3.14

perimeter of semicircle (p) = (2+pie)d/2 ...............(1)

p [PSR]=(2+3.14)10/2

=(5.14)5

=25.7

p [PAQ]=(2+3.14)7/2

=(5.14)3.5

=17.99

p [QTR]=(2+3.14)3/2

=(5.14)1.5

=7.71

Perimeter of shaded part={ (p[PSR]-p[PAQ])+p[QTR]} ............(construction)

={(25.7-17.99)+7.71}

={(7.71)+7.71}

=15.42

Hence. perimeter of shaded part is 15.42

blowny: hey here its the perimeter to be solve out not the area

spurthi122: correction made

blowny: okay......

blowny: but its wrong

Roshan1694: u r doing wrong

blowny: whi

Roshan1694: only pi r

Roshan1694: she take( 2+pi)d/2

Roshan1694: and do +everywhere

Roshan1694: but spurthi take - in PAQ

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