Question

In the below figure PT is tangent to a circle with
centre 0, PT = 12 cm, AP = 8 cm. Find the
radius of the circle.
C​

Answer 1

Answer:

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Answer 2

Given, PT=30cm

OT is the radius of a cicle

$\therefore$OT will be half of given diameter OT = 16cm

∠OTP = 90⁰

(tangent is perpendicular to radius at point of contact)

$\sf{Using \: Pythagoras \: theorem}$

$\sf{ \purple{ \underline{(OP)^{2} = (OT)^{2} + (TP)^{2} }}}$

$\sf{OP^{2} = {16}^{2} + {30}^{2} }$

$\sf{OP^{2} = 1156 }$

$\sf{OP = \sqrt{1156} }$

$\sf \large { \underline{ \underline{\fbox {\red{OP = 34cm}}}}}$