Math, asked by Anonymous, 1 year ago

In the below figure, the vertices of ΔABC are A(4, 6), B(1, 5) and C(7, 2). A line-segment DE is
drawn to intersect the sides AB and AC at D and E, respectively, such that
AD/AB=AE/EC=1/3
Calculate the area of ΔADE and compare it with area of ΔABC.

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Answers

Answered by vivek430
0
D is the mid point of AB so by mid point theorm( x1+x2÷2)(y1+y2÷2)
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