Question

in the below given figure, 0 is the center of a circle, find the value of x.​

Answer 1

Answer:

we can solve this question by using two concept which are", angle inscribed by the same arc on the circumference of a circle are always equal." and“circularcular angles are always right angle."

Step-by-step explanation:

firstly we will write the given figure,

angle abc=40°, angle bdc= x°. ....................(1)

To find the angle BDC we should know the key concept given below,

concept: Angles inseribed the same arc on the circumference of a circle always equal.

i.e. angle bac=angle bdc. .....................(2)

Also O is the centre of the circle AB is the diameter, which can be easily seen from the figure and therefore angle ACB is a semicircular angle.

as we know tl semicircular angle are always rights therefore angle abc = 90°. ..........................(3)

consider ∆ABC,

angle abc + angle bac=180°. [angles of a triangle]

since 90°+40°+angle bac=180°. [from (1) and (2) ]

". angle bac=180°-130°

". angle bac= 50°

now, to find the value of angle bdc rewrite the equation (2) which we have evaluated earlier

angle bac = angle bdc

put, angle bac = 50°

since angle bdc=50°

If we refer equation (1 ) then we can write,

x° = angle bdc

since x° = angle bdc = 50°

since The value of x° in the following figure is 50°

1. note: If we see the geometry of figure we can easily calculate the value of x° by considering diameters perpendicular to each other and therefore considering the angle B to be 90° proceeding further from solution but don't proceed like this as condition is not mention in the problem and there is no sign of showing perpendicular in the figure.

this is your answer. salmon rider@