in the below given figure o is the midpoint of AB and CD prove that AC = BD and AC// BD
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In triangles AOC and BOD, we have
AO = BO (O, the midpoint of AB);
∠AOC=∠BOD, (vertically opposite angles);
CO=OD, (O, the midpoint of CD)
So by SAS postulate we have
△AOC≅△BOD.
Hence, AC = BD, as they are corresponding parts of congruent triangles.
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