Question

in the binomial expansion of (x-2/x)^8 the middle term is

Answer 1

$5 {yy { { { {y { {cdthjehssos}^{2} }^{?} }^{2} }^{2} }^{2} }^{2} }^{2}$

Answer 2

Answer: The middle term is 1120.

Step-by-step explanation:

Since we have given that

$(x-\dfrac{2}{x})^8$

Here, n = 8

which is an even number.

so, Middle term would be

$\dfrac{n}{2}+1\\\\=\dfrac{8}{2}+1\\\\=4+1\\\\=5^{th}\ term$

So, the value of 5th term would be

$T_5=T_{5+1}=^8C_4x^4(\dfrac{2}{x})^4=70x^4\times \dfrac{16}{x^4}=1120$

Hence, the middle term is 1120.