Math, asked by sonalika, 6 months ago

in the blanks choosing
The number of solutions of 2 sin 0-1=0 is

Answers

Answered by SUNNY90850

1

2sinθ-1=0

sinθ=1/2

sinθ=sinΠ/6

θ=nΠ+(-1)^n.Π/6

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