In the Bohr model of the hydrogen atom an electron is pictured rotating in a circle (with a radius of 0.5 x 10^-10 m) about the positive nucleus of the atom. The centripetal force is furnished by the electric attraction of the positive nucleus for the negative electron. How large is this force if the electron is moving with a speed of 2.3 x 10^6 m/s? (The mass of an electron is 9 x 10^-31 kg.)
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Answer:
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Explanation:
Speed = 2.2×10
6
radius = 5×10
−11
m
time taken =
speed
2πr
=
2.2×10
6
2×π×5×10
−11
=
7×22×10
6
2×22×10×5×10
−11
=
7
10
×10
−16
Current
t
q
(1e=1.6×10
−19
C)
=
10×10
−16
1.6×10
−19
×7
=
100
1.6
×10
−3
×7
=112×10
−5
A
=112×10
−5
×1000mA
=1.12mA
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