Chemistry, asked by jsgsnsdfzjzjs3173, 9 months ago

In the boiler of a power plant are tubes through which water flows as it is brought from 0.8mpa, 150c (h=632.6 kj/kg, s= 1.8418 kj/khk) to 0.8 mpa, 250c (h=2950kj/kg, s=7.0384 kj/kgk). Combustion gases passing over the tubes cool from 1067c to 547c. These gases may be considered as air (ideal gas) having cp =1.005 kj/kgk. As suming steady state and neglecting any heat loss, and k.E. And p.E. Effects, determine (a) the mass flow rate of combustion gases per kg of steam, (b) the loss of exergy per kg steam and (c) the second law efficiency. Take t=25c, p=1 atm.

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Answered by diamondpragati
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