Question

in the calendar of a month 4days are shown in algebric form?

1 give two different values for"a" and complete the squares is the calendar?

2. find the sum of the numbers in the square it's a multiple of 4 ?

3 using algebric prove that the sum of numbers in such a square of calendar is always a multiple of 4 ?
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Answer 1

Answer:

The equation is:

x+(x+1)+(x+7)+(x+8)=80

Now let's collect like terms and we get:

4x+16=80

and it is simple equations work from here

4x+16=80

4x=64

x=16

Therefore, the four numbers on the calendar are 16, 17, 23, 24.

To prove it works,

16+(16+1)+(16+7)+(16+8)=80

16+17+23+24=80

Thanks for reading and I hope this helped

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