In the case of ionic bonding, the molecule is stable as long the number of bonding electrons is (a) Equal to the number of anti-bonding electrons. (b) Less than the number of anti-bonding electrons. (c) Greater than the number of anti-bonding electrons. (d) Equal to the number of anti-bonding neutrons.
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Option 3 : Greater than the number of antibonding electrons
Detailed Solution
Concept:
Bond factor (BF) is defined as:
BF= ( Bonding electrons in the molecule – antibonding electrons in the molecule)
Observations:
When the bond factor is “zero”, the molecule is highly unstable. Hence the bond factor must be greater than zero.
Based on this, if the bond factor is assumed as 1, i.e.
1 = ( Bonding electrons in the molecule – anti-bonding electrons in the molecule)
2 = Bonding electrons in the molecule – antibonding electrons in the molecule
Bonding electrons in the molecule = 2 + antinbonding electrons in the molecule
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