Question

In the cation [H-C-N-Xe-F]+ which is linear, the hybridisation of C, N and Xe atoms respectively are A) sp, sp, sp B) sp, sp², sp³ C) sp, sp, sp³d D) sp², sp, sp³d please answer don't spam its very urgent i ill give you brainliest ​

Answer 1

Answer:It is 0.5(V+M-C+A)

V= No. Of valence electrons of central atom

M- No. Of monovalent atom

C- Total Cation charge

A- Total Anion charge

For example-:

CH4

So CH4 has central atom carbon which has four valence electrons and it has 4 monovalent hydrogen atom. As there is no plus or minus charge on compound so

0.5(4+4)= 4

2) SO4^2-

The central atom is sulphur with 6 valence electrons. It has no monovalent atom. The total Anion charge is 2

So 0.5(6+2) = 4

Now match the number you get with:-

Sp- 2

Sp2-3

Sp3-4

Sp3d-5

Sp3d2- 6 and so on

The above two species hence have sp3 hybridisation.

Note:-

Monovalent atoms means hydrogen, alkali metals and group 17 elements

If charge on compound is -2 you have to take 2 and never take the sign. Only the number. Remember the number of positive charge is to be subtracted in formula and vice versa

Rarely in 2–3 compound the formula won't work.

Explanation:

Answer 2

Answer:

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Explanation:

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