Math, asked by skijajahmmed, 1 year ago

in the certain examination, 77% candidates passed in English and 34% failed in mathematics. if 13% failed in both the subjects and 784 candidates passed in both the subject, than the total number of candidates was​

Answers

Answered by Aryavart56
19

English passing students = 77%

Maths passed students = (100 – 34)

⇒ 66%

Common passed = (100 – 13) = 87%

So, only passed ⇒ 77 + 66 – 87

⇒ 143 – 87

⇒ 56%

So, 56% of students = 784

So, total students = (784 × 100)/56 = 1400


skijajahmmed: 87 subtract kiyu huya...?
Aryavart56: yes
skijajahmmed: 87 pass hain but subtract keyse hua..?
Answered by head8250
0

Answer:

lol xr and i am a anbu lol I

Step-by-step explanation:

1400

Similar questions