Question

in the certain fraction the denominator is 4 less than the numerator if 3 is added to both the numerator and denominator the resulting fraction is equal to 9 by 7 the find original fraction​

Answer 1

Answer:

Step-by-step explanation:Let the fraction be x/x+4

Now when 3 is added to both numerator and denominator it becomes

x+3/x+4+3=9/7

x+3/x+7=9/7

On cross multiplying we get,

7x+21=9x+63

21-63=2x

-42/2=x

x=-21

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Answer 2

Answer:

Step-by-step explanation:

Let the fraction be x/x-4

When we add 3 to both n/d

Then, x+3/x-4+3=9/7

x+3/x-1=9/7

Now cross multiply both numerator and denominator

So, 7(x+3)=9(x-1)

7x+21=9x-9

- 2x= - 30

x=30/2

x=15 (this is numerator)

Denominator =x-4

=15-4

=11

=n/d is 15/11

Ans: hence, the original fraction is 15/11