Question

in the circle AB is a tangent drawn to a circle with center o write the measure of aOPA​

Answer 1

Step-by-step explanation:

Given, ∠AOB=110

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In △AOB

OA=OB (Radius of the circle)

Thus, ∠OAB=∠OBA (Isosceles triangle property)

Sum of angles of the triangle = 180

∠AOB+∠OAB+∠OBA=180

110+2∠OBA=180

∠OBA=35

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Since, PQ is a tangent touching the circle at B.

Thus, ∠OBQ=90

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Now, ∠ABQ+∠OBA=90

∠ABQ+35=90

∠ABQ=55

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