Question

.In the circle ,O is the centre. AOC is a straight line. Angle BAO is 24° and Angle ADO is 42°. Find angle CAD, ACB, BCD.​​

Answer 1

Step-by-step explanation:

a) angle CAD= angle ODA ( in triangle OAD, OA-OD(same radius) angels opp to equal sides are equal)

hence angle CAD=42

b)angle b =90(angle subtended by diameter) hence using angle sum property in triABC, angle ACB-66

c) in tri OAD,

Angle AOD=180-(42+42) sum prop.) --(using angle

=> 96------

angleACD=1/2 Angle AOD ( angle subtende by an arc at centre is double the angle subtended...)

hence angle ACD =1/2 x 96(from eq1) ----eq3

angleACD=48-

from eq 3,and eq4,

angle BCD= 48+66

=114 degree...

Answer 2

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na na tb per bhi ab aapko nhi dena hai thanks aapne bahut deliya hai

kiske ??