Question

In the circle of radius 3.5 pair of tangent from external point 8 cm away from the centre

Answer 1

what is ur doubt in this Question .?

Answer 2

I GUESS WE HAVE TO FIND THE LENGTH OF THE TANGENT....

we know that PA=QA(tangents drawn from an external Point are equal)

now,

consider ΔOPA

∠OPA=90°(The tangent at any point of a circle is perpendicular to the radius through the point of contact)

OP=3.5 cm (given)

AO=8 cm(given)

by Pythagoras theorem

OA²=PA²+PO²

PA²=OA²-PO²

PA²=(8)²-(3.5)²

PA²=64 - 12.25

PA²= 51.75

PA=√51.75

PA= 7.2(approx)

∴PA=QA=7.2

hope it helps....

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