Question

In the circle with centre O, angle CAD =40 °then, find angle B and angle ACD

Answer 1

Given : circle with centre 'O' angle CAD=40°  

To Find :  angle B , D and angle ACD

Solution:

Ad per given figure  

AC is Diameter  as O lies on AC

Hence ∠ B = ∠D  = 90°   ( as ends of dimeter forms a right angle at rest of circle )  

∠CAD + ∠D + ∠ADC = 180°   ( Sum of angles of triangle)

=> 40° + 90° + ∠ADC = 180°

=> 130° + ∠ADC = 180°

=> ∠ADC = 50°  

∠ B = ∠D  = 90°  

∠ADC = 50°  

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