In the circle with centre 'o',<CAD=40 then find angle B and angle ACD
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Given : circle with centre 'O' angle CAD=40°
To Find : angle B , D and angle ACD
Solution:
Ad per given figure
AC is Diameter as O lies on AC
Hence ∠ B = ∠D = 90° ( as ends of dimeter forms a right angle at rest of circle )
∠CAD + ∠D + ∠ADC = 180° ( Sum of angles of triangle)
=> 40° + 90° + ∠ADC = 180°
=> 130° + ∠ADC = 180°
=> ∠ADC = 50°
∠ B = ∠D = 90°
∠ADC = 50°
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