Question

In the circuit below, calculate
1) Calculate total effective resistance.
2) The total current through the circuit.
3) Potential difference across 4ohm and 3ohm​

Answer 1

Answer:

gorgeous here is yur answer

Explanation:

Answer: The total effective resistance is 3 ohm, the current through 6 ohm is 1 A and the potential difference across 4 ohm is 4 volt.

Explanation:

Given that,

Resistance R_{1} = 4\text{\O}megaR

1

=4Ømega

Resistance R_{2} = 2\text{\O}megaR

2

=2Ømega

Resistance R_{3} = 6\text{\O}megaR

3

=6Ømega

According to the figure,

R_{1}R

1

and R_{2}R

2

are connected in series then,

The resistance R is

R = R_{1}+R_{2}R=R

1

+R

2

R = 4\text{\O}mega+2\text{\O}megaR=4Ømega+2Ømega

R = 6\text{\O}megaR=6Ømega

RR and R_{3}R

3

are connected in parallel

(a). The effective resistance is

\dfrac{1}{R_{eff}}=\dfrac{1}{R}+\dfrac{1}{R_{3}}

R

eff

1

=

R

1

+

R

3

1

\dfrac{1}{R_{eff}}=\dfrac{1}{3}

R

eff

1

=

3

1

R_{eff} = 3 \text{\O}megaR

eff

=3Ømega

So, the total effective resistance is 3 ohm.

(b). The current through 6 ohm resistor is

Using ohm's law

V = i\times RV=i×R

i = \dfrac{V}{R}i=

R

V

i = \dfrac{6 V}{6\text{\O}mega}i=

6Ømega

6V

i = 1 Ai=1A

(c). The potential difference across 4 ohm resistor

V = i\times RV=i×R

V = 1 A\times 4\text{\O}megaV=1A×4Ømega

V = 4 voltV=4volt

The potential difference is 4 volt.

Hence, The total effective resistance is 3 ohm, the current through 6 ohm is 1 A and the potential difference across 4 ohm is 4 volt.

Answer 2

Explanation:

Hope you are clear with this short answer. thankyou