Question

In the circuit below resistors R1 and R2 are in parallel and have resistances of 8 Ω and 4 Ω,
respectively. The current passing through R1 is 0.2 A. Find the voltage across resistor R2 and
the current passing through the same resistor.

Answer 1

Answer:

Hence the current I2 through R2 is equal to 0.8 A. We now use Ohm's law to find the voltage V2 across resistor R2. In the circuit below resistors R1 and R2 are in parallel and have resistances of 8 Ω and 4 Ω, respectively. The current passing through R1 is 0.2 A.

Answer 2

Answer:

The voltage across resistor  $R_2$ is 1.67 volt.

The current passing through the resistor $R_2$ is 0.42 A.

Explanation:

• Equivalent resistance:

The two resistances are $R_1$ = 8Ω and $R_2$ = 4Ω.

$R_1$ and  $R_2$ are parallel. So equivalent resistance, R = $\frac{R_1R_2}{R_1+R_2}$  Ω

                                                                                R = $\frac{8\times4}{8+4}$ = 2.66 Ω

Suppose potential difference across the ends is 'V' and 'I' is the whole current, then we can write V = IR  [From Ohm's law]

                                           I = $\frac{V}{R}$ = $\frac{V}{2.66}$

• Current through $R_1$ is, $I_1$ = 0.2A

        Current through $R_2$ is, $I_2$ = $\frac{V}{R_2}$ = $\frac{V}{4}$

       In parallel combination we know that I = $I_1$ + $I_2$

                                                               $\frac{V}{2.66}$ = 0.2 + $\frac{V}{4}$ [putting all the values]

                                                                 V = 1.67 volt

  The voltage across resistor  $R_2$ is 1.67 volt.

   Now  $I_2$ = $\frac{V}{4}$ = 0.42 A

  The current passing through the resistor $R_2$ is 0.42 A.

To know more about parallel and series connection visit the link below:

https://brainly.in/question/19878620

https://brainly.in/question/7930250