Question

In the circuit below resistors R1 and R2 are in series and have resistances of 5 Ω and 10 Ω, respectively. The voltage across resistor R1 is equal to 4 V. Find the current passing through resistor R2 and the voltage across the same resistor.​

Answer 1

Given :

• R₁ = 5Ω
• R₂ = 10Ω
• R₁ and R₂ are connected in series.
• Voltage across R₁ = 4V

To find :

• Current passing through R₂
• Voltage across R₂

Solution :

In series combination, Current remain same across all resistor.

Therefore first of all we will find current across resistor R₁

We know that, V = iR

Here,

• V = voltage across resistor
• i = current passing through resistor
• R = Resistance of resistor

V₁ = i × R₁

➝ 4V = i × 5Ω

➝ i = 4/5

➝ i = 0.8 A

As , R₁ and R₂ are connected in series, current passing through R₁ will same as current passing through R₂

Therefore current passing through R₂ = 0.8 A

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Now , using V= iR

➝ V₂ = i × R₂

➝ V₂ = 0.8A × 10Ω

➝ V₂ = 8V

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ANSWER :

• Current = 0.8 A
• Voltage = 8 V