Question

In the circuit calculate resistance reading of ammeter reading of ammeter

Answer 1

Answer:

Components connected in parallel are connected so the same voltage is applied to each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.  To find the total resistance of all components, the reciprocals of the resistances of each component is added and the reciprocal of the sum is taken. Hence, the Total resistance will always be less than the value of the smallest resistance. That is, Rtotal1=R11+R21...Rn1,R=Rtotal−1. . Components 

Answer 2

Answer:

34

Explanation:

Two point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two chargesTwo point charges +q and-q are placed at a point d distance apart draw the line on which the resultant field is parallel to the line joining the two charges