in the circuit current through 2k resistance is
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Answer:
I=27A
Step-by-step explanation:
1/R=1/R1 +1/R2+1/R3+1/R4+1/R5
1/R=1+1+1+1+0.5
1/4.5=R
2/9=R
V=6V
V=IR
6V=I×2/9 Ohm
6÷2/9=I
6×9/2=I
9×3=I
I=27 A
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