Math, asked by biswaspronab15, 9 months ago

in the circuit current through 2k resistance is​

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Answers

Answered by adkale212005
1

Answer:

I=27A

Step-by-step explanation:

1/R=1/R1 +1/R2+1/R3+1/R4+1/R5

1/R=1+1+1+1+0.5

1/4.5=R

2/9=R

V=6V

V=IR

6V=I×2/9 Ohm

6÷2/9=I

6×9/2=I

9×3=I

I=27 A

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