Question

In the circuit diagram, calculate the electric current through branch BC

Answer 1

Answer:

4A

Explanation:

At B junction currents from two direction each having magnitude log 2 A is coming towards it so 2+2=4A of current must be leaving from junction B.

So current in the branch BC is 4A.

This is to verify kirchoff's law of junction.

Answer 2

At the junction the law of conservation of charge is valid.

The sum of current flowing in the circuit is equal to the sum of the currents flowing out of the junction in an electrical circuit.

This is known as Kirchhoff's junction rule.

At junction/ node B, we apply  Kirchoff's current law.

We get,

The incoming current through $I_{AB}$= 2 A

The current through $I_{BC}$ = 2 A + $I_{AB}$

Thus, the current through BC is 4 A.

Hence, the correct answer is 4 Ampere.