Question

In the circuit diagram given alongside, the current flowing across 5 ohm resistor is 1 amp. Find the current flowing through the other two resistors. (3 resistors are in parallel - 5 ohm, 4 ohm, 10 ohm)

Answer 1

A= 1
R = 5
So V = 1*5 = 5
In parallel circuit they access equal voltages.so,
In 4ohm =)
A = 5/4 = 1.2a (approx.)
In 10ohm =)
A = 5/10 = 0.5a .

Answer 2

Answer : The current flowing through 4 ohm and 10 ohm resistance are 1.25 and 0.5 ampere respectively.

Solution : Given,

Resistance, $R_1$ = 5 ohm

Resistance, $R_2$ = 4 ohm

Resistance, $R_3$ = 10 ohm

Current flowing in $R_1$ = 1 A

First we have to calculate the voltage in the circuit.

Using ohm's law :

$V=I\times R$

where,

V = voltage

I = current

R = resistance

Now put all the given values in this formula, we get the voltage.

$V=(1A)\times (5\Omega)=5V$

Now we have to calculate the current flowing through the other two resistors.

As the three resistors are in parallel. So, the voltage will always be same for all the resistors but current flowing through the resistors will be different.

$I_2=\frac{V}{R_2}=\frac{5}{4}=1.25A\\\\I_3=\frac{V}{R_3}=\frac{5}{10}=0.5A$

Therefore, the current flowing through 4 ohm and 10 ohm resistance are 1.25 and 0.5 ampere respectively.