Question

in the circuit diagram given below 5 resistance of 10 ohm 40 ohm 30 ohm 20 ohm and 60 ohm are connected as shown to a 12 volt battery calculate total resistance in the circuit and total current flowing in the circuit

Answer 1

Given,

Resistance R1 = 10 Ω

Resistance R2 = 40 Ω

Resistance R3 = 30 Ω

Resistance R4 = 20 Ω

Resistance R5 = 60 Ω

Voltage V = 12 V

To find,

We have to calculate the total resistance and total current in the circuit.

Solution,

The total resistance in the circuit and the total current flowing through it are 18 Ω and 0.67 A respectively.

R1 and R2 are connected in parallel and R3, R4, and R5 are also connected in parallel.

1/Rp = 1/R1 + 1/R2

1/Rp = 1/10 +1/40

Rp =  8Ω

1/Rp' = 1/R3 + 1/R4 + 1/R5

1/Rp' = 1/30 + 1/20 + 1/60

Rp' = 10Ω

Now, Rp and Rp' are connected in series, then

Rs = Rp + Rp'

    =  8 +10

    = 18 Ω

Now, to calculate current

V = IR

I  = V/R

  = 12/18

  = 0.67 A

Hence, the total resistance in the circuit and the total current flowing through it are 18 Ω and 0.67 A respectively.

Answer 2

Answer:

The total resistance in the circuit and the total current flowing through it are 18 Ω and 0.67 A respectively.

Explanation:

• In context to the given question we have to find the Total resistance and total current in the circuit.

• Given, 5 Resistance of the circuit are

R1 = 10 Ω

R2 = 40 Ω

R3 = 30 Ω

R4 = 20 Ω

R5 = 60 Ω

And voltage is

Voltage V = 12 V

[AS THE CIRCUIT DIAGRAM IS NOT GIVEN, AS IT IS A NCERT QUESTION , SO BY CONSIDERING THAT CIRCUIT DIAGRAM]

• R1 and R2 are connected in parallel
• R3, R4, and R5 are also connected in parallel.

As R1 and R2 are in parallel;

Applying the formula of resistance connected in parallel, we get;

1/Rp = 1/R1 + 1/R2

1/Rp = 1/10 +1/40

Rp =  8Ω

Similarly,

R3, R4, and R5 are also connected in parallel

Applying the formula of resistance connected in parallel, we get;

1/Rp' = 1/R3 + 1/R4 + 1/R5

1/Rp' = 1/30 + 1/20 + 1/60

Rp' = 10Ω

• Now, Rp and Rp' are connected in series, then

Rs = Rp + Rp'

Rs = 8 +10 = 18 Ω

Now, to calculate Total current

V = IR

I  = V/R = 12/18

= 0.67 A

Hence,

The total resistance in the circuit and the total current flowing through it are 18 Ω and 0.67 A respectively.