Question

In the circuit diagram given below, three resistors R1, R2 and R3 of 5Ω, 10Ω

and 30Ω respectively are connected as shown:​

Answer 1

Answer:

V=12V

R1, R2 and R3 are connected in parallel.

(a) Current through R1 = V/R1 = 12/5 = 2.4 A

Current through R2 = V/R2 = 12/10 = 1.2 A

Current through R3 = V/R2 = 12/30 = 0.4 A

(b) Total current in the circuit = 2.4 + 1.2 + 0.4 = 4 A

(c) Total resistance in the circuit=R

1/R = 1/R1+ 1/R2 + 1/R

1/R = 1/5 + 1/10 + 1/30

1/R = 10/30

R = 3 ohm

Answer 2

Explanation:

HEY MATE YOUR ANSWER IS HERE ^_^

(C) 1/Rnet = 1/R1 + 1/R2 + 1/R3

1/Rnet = 1/5 + 1/10 + 1/30 = 1/3

Rnet = 3 OHM

(B) I = V/R = 12/3 = 4 A

(A) CURRENT THROUGH 5 OHM = V/R = 12/5 = 2.4 A

CURRENT THROUGH 10 OHM = V/R = 12/10 = 1.2 A

CURRENT THROUGH 30 OHM = V/R = 12/30 = 0.4 A

PLEASE MAKE ME A BRAIN LIST ANSWER FOR THE QUESTION.