Question

In the circuit diagram shown, each battery is ideal having an e.m.f. of 1 volt. Each resistor has a resistance of 1 2. Ammeter (A) has a resistance of 1 2. Find the reading of the ammeter and the total thermal power produced in the circuit

Answer 1

Given that,

Emf = 1 V

Each resistance = 12Ω

According to figure,

R₁ and R₂ in series

We need to calculate the equivalent resistance

Using formula of series

$R=R_{1}+R_{2}$

Put the value into the formula

$R=12+12$

$R=24\ \Omega$

R and R₃ is connected in parallel

We need to calculate the equivalent resistance

Using formula of parallel

$\dfrac{1}{R'}=\dfrac{1}{R}+\dfrac{1}{R_{3}}$

Put the value into the formula

$\dfrac{1}{R'}=\dfrac{1}{24}+\dfrac{1}{12}$

$R'=8\ \Omega$

We need to calculate the current

Using ohm's law

$V=IR$

$I=\dfrac{V}{R}$

Where, V = voltage

I = current

R = resistance

Put the value into the formula

$I=\dfrac{1}{8}$

$I=0.125\ A$

We need to calculate the power produced in the circuit

Using formula of power

$P=I^2R$

Put the value into the formula

$P=(0.125)^2\times8$

$P=0.125\ watt$

Hence, The current is 0.125 A.

The power produced in the circuit is 0.125 watt.